QGraphicsView实现简易地图8『缓存视口周边瓦片』

前文链接：QGraphicsView实现简易地图7『异步加载-多瓦片-无底图』
前7篇的地图加载，都采用最少瓦片数量的算法，即用最少数量的瓦片覆盖视口，以获得最快的加载速度。但是这样会带来一个问题，那就是每当移动地图时，视口周边的瓦片才会加载，这样会造成地图的延时甚至卡顿，而这会令用户感到非常反感。为此，需要在之前的算法上进行改进，即加载覆盖视口的最少瓦片后，立即加载视口周边瓦片。
1、动态演示效果

2、获取视口及周边瓦片代码：以视口宽高的一半向四周扩展

QRect CommonUtility::getViewAndAroundTileCoords(int tempTileTop, int tileLeft, int tempTileBottom, int tileRight, int level, vector<TileCoord> &vecTileCoord)
{
	// <1> 视口
	for (int row = tempTileTop; row <= tempTileBottom; ++row)
	{
		for (int col = tileLeft; col <= tileRight; ++col)
		{
			vecTileCoord.push_back(TileCoord(col, row));
		}
	}

	int mapSize = pow(2, level);
	int tileW = tileRight - tileLeft + 1;
	int tileH = tempTileBottom - tempTileTop + 1;
	int tempTileT, tempTileL, tempTileB, tempTileR;
	int tileT, tileL, tileB, tileR;

	// <2> 上侧
	tileT = tempTileT = qMax(tempTileTop - tileH / 2, 0);
	tempTileB = tempTileTop - 1;
	tempTileL = qMax(tileLeft - tileW / 2, 0);	
	tempTileR = qMin(tileRight + tileW / 2, mapSize - 1);
	for (int row = tempTileT; row <= tempTileB; ++row)
	{
		for (int col = tempTileL; col <= tempTileR; ++col)
		{
			vecTileCoord.push_back(TileCoord(col, row));
		}
	}

	// <3> 下侧
	tempTileT = tempTileBottom + 1;
	tileB = tempTileB = qMin(tempTileBottom + tileH / 2, mapSize - 1);
	tempTileL = qMax(tileLeft - tileW / 2, 0);
	tempTileR = qMin(tileRight + tileW / 2, mapSize - 1);
	for (int row = tempTileT; row <= tempTileB; ++row)
	{
		for (int col = tempTileL; col <= tempTileR; ++col)
		{
			vecTileCoord.push_back(TileCoord(col, row));
		}
	}

	// <4> 左侧
	tileL = tempTileL = qMax(tileLeft - tileW / 2, 0);
	tempTileR = tileLeft - 1;
	for (int row = tempTileTop; row <= tempTileBottom; ++row)
	{
		for (int col = tempTileL; col <= tempTileR; ++col)
		{
			vecTileCoord.push_back(TileCoord(col, row));
		}
	}

	// <5> 右侧
	tempTileL = tileRight + 1;
	tileR = tempTileR = qMin(tileRight + tileW / 2, mapSize - 1);
	for (int row = tempTileTop; row <= tempTileBottom; ++row)
	{
		for (int col = tempTileL; col <= tempTileR; ++col)
		{
			vecTileCoord.push_back(TileCoord(col, row));
		}
	}

	return QRect(tileL, tileT, (tileR - tileL + 1), (tileB - tileT + 1));
}