C语言 | Leetcode C语言题解之第327题区间和的个数

发布于:2024-08-12 ⋅ 阅读:(137) ⋅ 点赞:(0)

题目:

题解:

int countRangeSumRecursive(long long* sum, int lower, int upper, int left, int right) {
    if (left == right) {
        return 0;
    } else {
        int mid = (left + right) / 2;
        int n1 = countRangeSumRecursive(sum, lower, upper, left, mid);
        int n2 = countRangeSumRecursive(sum, lower, upper, mid + 1, right);
        int ret = n1 + n2;

        // 首先统计下标对的数量
        int i = left;
        int l = mid + 1;
        int r = mid + 1;
        while (i <= mid) {
            while (l <= right && sum[l] - sum[i] < lower) l++;
            while (r <= right && sum[r] - sum[i] <= upper) r++;
            ret += (r - l);
            i++;
        }

        // 随后合并两个排序数组
        long sorted[right - left + 1];
        memset(sorted, 0, sizeof(sorted));
        int p1 = left, p2 = mid + 1;
        int p = 0;
        while (p1 <= mid || p2 <= right) {
            if (p1 > mid) {
                sorted[p++] = sum[p2++];
            } else if (p2 > right) {
                sorted[p++] = sum[p1++];
            } else {
                if (sum[p1] < sum[p2]) {
                    sorted[p++] = sum[p1++];
                } else {
                    sorted[p++] = sum[p2++];
                }
            }
        }
        for (int i = 0; i < right - left + 1; i++) {
            sum[left + i] = sorted[i];
        }
        return ret;
    }
}

int countRangeSum(int* nums, int numsSize, int lower, int upper) {
    long long s = 0;
    long long sum[numsSize + 1];
    sum[0] = 0;
    for (int i = 1; i <= numsSize; i++) {
        sum[i] = sum[i - 1] + nums[i - 1];
    }
    return countRangeSumRecursive(sum, lower, upper, 0, numsSize);
}

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