RedisTemplate 序列化成功,反序列化失败List, Set, Map失败

发布于:2024-03-02 ⋅ 阅读:(164) ⋅ 点赞:(0)

RedisTemplate 序列化成功,反序列化失败List, Set, Map失败

序列化成功,反序列化失败

异常信息

Caused by: com.fasterxml.jackson.databind.exc.InvalidTypeIdException: Could not resolve type id '6' as a subtype of `java.lang.Object`: no such class found
 at [Source: (byte[])"[6,7,1,2,3,4,5]"; line: 1, column: 4]
Caused by: com.fasterxml.jackson.databind.exc.MismatchedInputException: Unexpected token (START_OBJECT), expected VALUE_STRING: need String, Number of Boolean value that contains type id (for subtype of java.lang.Object)
 at [Source: (byte[])"[

RedisTemplate配置

首先确定RedisTemplate序列化器设置正确

@Bean
public RedisTemplate<Object, Object> redisTemplate(RedisConnectionFactory redisConnectionFactory) {
     RedisTemplate<Object, Object> redisTemplate = new RedisTemplate<>();
     redisTemplate.setConnectionFactory(redisConnectionFactory);

     //String的序列化方式
     // 使用GenericJackson2JsonRedisSerializer 替换默认序列化(默认采用的是JDK序列化)

     //序列号key value
     redisTemplate.setKeySerializer(RedisSerializer.string());
     redisTemplate.setValueSerializer(RedisSerializer.json());
     redisTemplate.setHashKeySerializer(RedisSerializer.string());
     redisTemplate.setHashValueSerializer(RedisSerializer.json());

     redisTemplate.afterPropertiesSet();
     return redisTemplate;
 }

异常原因

使用了List.of(), Set.of(), Map.of()等方法导致序列化时没有类型
使用stream api 的 toList 方法

错误代码示例

 Map<String, List<Integer>> map = new HashMap<>();
 Map<Integer, Integer> map2 = Map.of(1, 2, 3, 4);
 List<Integer> list = List.of(1, 2, 34, 54, 5);
 ArrayList<Integer> arrayList = new ArrayList<>(list);
 map.put("1", list);
 redisTemplate.opsForHash().putAll("test:1", map);
 redisTemplate.opsForHash().put("test:2", "1", arrayList);
 Set<Integer> nums = Set.of(1, 2, 3, 4, 5, 6, 7);
 redisTemplate.opsForValue().set("test:3", nums);

这是错误的序列化,会导致反序列化失败
在这里插入图片描述

正确的序列化的带有java类型的
在这里插入图片描述

解决方法

不使用List.of(), Set.of(), Map.of() 等静态方法
使用.collect(Collectors.toList())代替stream().toList()

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