1.整理思维导图
2.把上课没做完的结构体大小求完(写出过程)
3.把枚举部分的练习题，再做一遍
4.三种验证大小端存储大的代码写一遍
1.思维导图在最后
2.结构体大小
struct data{ 1233000044444444，16字节
char t1;
char t2;
unsigned short t3;
unsigned long t4;
};
struct data{ 100022223300，12字节
char t1;
int t2;
short t3;
};
struct s1 100022223000，12字节
{
char c1;
int i;
char c2;
};
struct s2 12003333，8字节
{
char c1;
char c2;
int i;
};
typedef struct Test 1100000000002222222222223333，28字节
{
short a;
struct 111122223000,12字节
{
int b;
double c;
char d;
}p;
int e;
}Test;
typedef struct Test 110000000000000022222222222222223333，36字节
{
short a;
struct 1111222222222230,16字节
{
int b;
double c[10];
char d;
};
int e;
}Test;
struct c{ 100022223300，12字节
char b;
int a;
short c;
};
struct c{ 12223，5字节
char a;
char b[3];
char c;
};
typedef struct 111120003333333340000000555555556666，36字节
{
int b;
char a;
long e;
char c;
float d;
double t;
}node;
3.枚举
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
#include <math.h>
typedef enum
{
LED_1,
LED_2,
LED_3
}LED;
typedef enum
{
ON,
OFF
}LED_CON;
void init(LED L)
{
switch(L)
{
case LED_1:
printf("初始化了LED_1灯\n");
break;
case LED_2:
printf("初始化了LED_2灯\n");
break;
case LED_3:
printf("初始化了LED_3灯\n");
break;
}
}
void con(LED L,LED_CON C)
{
switch(L)
{
case LED_1:
switch(C)
{
case ON:
printf("打开了LED_1灯\n");
break;
}
break;
case LED_2:
switch(C)
{
case ON:
printf("打开了LED_2灯\n");
break;
}
break;
case LED_3:
switch(C)
{
case ON:
printf("打开了LED_3灯\n");
break;
}
break;
}
}
int main(int argc, const char *argv[])
{
init(LED_1);
con(LED_2,ON);
return 0;
}
4.大小端存储
一、
int a=0x12345678;
char c=(char)a;
if(c==0x12)
{
printf("大端存储\n");
}else{
printf("小端存储\n");
}
二、
typedef union
{
short a;
char c;
}A;
A u.a=0x1234
if(u.c==0x12)
{
printf("大端存储\n");
}else{
printf("小端存储\n");
}
