Spring Boot项目误将Integer类型写成int来进行传参

发布于:2024-03-02 ⋅ 阅读:(60) ⋅ 点赞:(0)

在处理项目中Idea中无报错

问题:

localhost:8080/param/m2在浏览器中输入:localhost:8080/param/m2

产生报错:

This application has no explicit mapping for /error, so you are seeing this as a fallback.

Tue Feb 27 20:55:33 GMT+08:00 2024

There was an unexpected error (type=Internal Server Error, status=500).

Optional int parameter 'id' is present but cannot be translated into a null value due to being declared as a primitive type. Consider declaring it as object wrapper for the corresponding primitive type.

原因为:Spring Boot项目误将Integer类型写成int来进行传参

该项目具体的代码为:(错误示范)

@RestController
@RequestMapping("/param")
public class ParamController {

    @RequestMapping("/m1")
    public String m1(String name){
        return "这是你的姓名:"+name;
    }

    @RequestMapping("/m2")
    public String m2(String name,int id){  //错误代码,需要将int更改为Integer(包装类)
        return "序列号为:"+ id +"这是你的姓名:"+name;
    }
}

解决方案:

因此,正确的代码为:(正确示范)

@RestController
@RequestMapping("/param")
public class ParamController {

    @RequestMapping("/m1")
    public String m1(String name){
        return "这是你的姓名:"+name;
    }

    @RequestMapping("/m2")
    public String m2(String name,Integer id){  
        return "序列号为:"+ id +"这是你的姓名:"+name;
    }
}

重启程序,在浏览器输入:localhost:8080/param/m2?id=5&name=zhangsan

运行结果为:

在Postman中测试为:

Bug解决!!


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