刷题第11天

发布于:2024-03-08 ⋅ 阅读:(83) ⋅ 点赞:(0)

代码随想录刷题第11天 | 二叉树前中后序遍历

前序遍历

/**
 * Definition for a binary tree node.
 * struct TreeNode {
 *     int val;
 *     TreeNode *left;
 *     TreeNode *right;
 *     TreeNode() : val(0), left(nullptr), right(nullptr) {}
 *     TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}
 *     TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}
 * };
 */
class Solution {
public:
    void traversal(TreeNode *cur,vector<int>&vec){
        if (cur == nullptr) return;
        vec.push_back(cur->val);
        traversal(cur->left,vec);
        traversal(cur->right,vec);
    }
    vector<int> preorderTraversal(TreeNode* root) {
        vector<int>result;
        traversal(root,result);
        return result;
    }
};

中序遍历

/**
 * Definition for a binary tree node.
 * struct TreeNode {
 *     int val;
 *     TreeNode *left;
 *     TreeNode *right;
 *     TreeNode() : val(0), left(nullptr), right(nullptr) {}
 *     TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}
 *     TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}
 * };
 */
class Solution {
public:
    void traversal(TreeNode *cur,vector<int>&vec){
        if (cur == nullptr) return;
        traversal(cur->left,vec);
        vec.push_back(cur->val);
        traversal(cur->right,vec);
    }
    vector<int> inorderTraversal(TreeNode* root) {
        vector<int>result;
        traversal(root,result);
        return result;


    }
};

后序遍历

/**
 * Definition for a binary tree node.
 * struct TreeNode {
 *     int val;
 *     TreeNode *left;
 *     TreeNode *right;
 *     TreeNode() : val(0), left(nullptr), right(nullptr) {}
 *     TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}
 *     TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}
 * };
 */
class Solution {
public:
    void traversal(TreeNode *cur,vector<int>&vec){
        if (cur == nullptr) return;
        traversal(cur->left,vec);
        traversal(cur->right,vec);
        vec.push_back(cur->val);
    }
    vector<int> postorderTraversal(TreeNode* root) {
        vector<int>result;
        traversal(root,result);
        return result;

    }
};
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